Count the characters

Given a string S. Count the characters that have ‘N’ number of occurrences. If a character appears consecutively it is counted as 1 occurrence.

Example 1:

Input:

S = "abc", N = 1

Output: 3

Explanation: 'a', 'b' and 'c' all have 

1 occurrence.

Example 2:

Input: 

S = "codecodefun", N = 2

Output: 4

Explanation: 'c', 'o', 'd' and 'e' have

2 occurrences.

method :

take one h[] array. increment the value in h[] array for all characters in string, now traverse the h[] array and check the value of each character, if it is equal to N than increment c variable.
at the end return c.

c++  implementation :

int getCount (string s, int n)
        {
            int h[26]={0};

           for(int i=0;i<s.length();i++)
           {
                if(s[i]!=s[i-1])
                h[s[i]-'a']++;
           }

           int c=0;
           for(int i=0;i<26;i++)
           {
               if(h[s[i]-'a']==n)
               {
                   c++;
               }
           }
          return c;
        }

 

time complexity:0(n) where n is the length of the string.